Complex32 x = new Complex32(1f,2f);
Complex32 y = Complex32.FromPolarCoordinates(1f, Math.Pi);
Complex32 z = (x + y) / (x - y);
// a, b of type Complex32
a.Conjugate = b;
is equivalent to
// a, b of type Complex32
a = b.Conjugate
long x,y,d;
d = Fn.GreatestCommonDivisor(45,18,out x, out y);
-> d == 9 && x == 1 && y == -2
The
long x,y,d;
d = Fn.GreatestCommonDivisor(45,18,out x, out y);
-> d == 9 && x == 1 && y == -2
The 1, 2, 3 4, 5, 6 will be returned as 1, 4, 7, 2, 5, 8, 3, 6, 9 7, 8, 9
1, 2, 3 4, 5, 6 will be returned as 1, 2, 3, 4, 5, 6, 7, 8, 9 7, 8, 9
1, 2, 3 4, 5, 6 will be returned as 1, 4, 7, 2, 5, 8, 3, 6, 9 7, 8, 9
1, 2, 3 4, 5, 6 will be returned as 1, 2, 3, 4, 5, 6, 7, 8, 9 7, 8, 9
Xn = a * Xn−3 + c mod 2^32
http://www.jstatsoft.org/v08/i14/paper
x -> exp(x)-1
exp(power)-1
.x -> exp(x)-1
exp(power)-1
.(a,b) -> sqrt(a^2 + b^2)
sqrt(a2 + b2)
without underflow/overflow.(a,b) -> sqrt(a^2 + b^2)
sqrt(a2 + b2)
without underflow/overflow.(a,b) -> sqrt(a^2 + b^2)
sqrt(a2 + b2)
without underflow/overflow.(a,b) -> sqrt(a^2 + b^2)
sqrt(a2 + b2)
without underflow/overflow.N-1 - ' y = > coef[i] T (x/2) - i i=0Coefficients are stored in reverse order, i.e. the zero order term is last in the array. Note N is the number of coefficients, not the order. If coefficients are for the interval a to b, x must have been transformed to x -> 2(2x - b - a)/(b-a) before entering the routine. This maps x from (a, b) to (-1, 1), over which the Chebyshev polynomials are defined. If the coefficients are for the inverted interval, in which (a, b) is mapped to (1/b, 1/a), the transformation required is x -> 2(2ab/x - b - a)/(b-a). If b is infinity, this becomes x -> 4a/x - 1. SPEED: Taking advantage of the recurrence properties of the Chebyshev polynomials, the routine requires one more addition per loop than evaluating a nested polynomial of the same degree.