38 lines
556 B
C++
38 lines
556 B
C++
|
#include <stdio.h>
|
|||
|
|
#include <stdlib.h>
|
|||
|
|
#include <math.h>
|
|||
|
|
|
|||
|
|
int main(){
|
|||
|
|
int num ,i=0 , j=1 ,temp;
|
|||
|
|
printf("*** <20>̤p<CCA4>]<5D>˭<EFBFBD><CBAD>n<EFBFBD><6E><EFBFBD>l<EFBFBD>H<EFBFBD>]<5D>L<EFBFBD>{<7B><> ***\n\n<EFBFBD><EFBFBD><EFBFBD>J<EFBFBD>}<7D>j<EFBFBD><6A> ==> ");
|
|||
|
|
scanf("%d",&num);
|
|||
|
|
temp = num ;
|
|||
|
|
while(1){
|
|||
|
|
if(pow(i,2)<=temp) i++;
|
|||
|
|
else break;
|
|||
|
|
}
|
|||
|
|
i--;
|
|||
|
|
|
|||
|
|
printf("\n<EFBFBD>]<5D>ˤ覡<CBA4><E8A6A1><EFBFBD><EFBFBD><EFBFBD>Y<EFBFBD>z<EFBFBD><7A>\n\n");
|
|||
|
|
|
|||
|
|
while(1){
|
|||
|
|
if(temp>=i){
|
|||
|
|
printf("<EFBFBD><EFBFBD>%d<>ơA%d<><64>\n",j,i);
|
|||
|
|
temp -= i;
|
|||
|
|
j++;
|
|||
|
|
}else if(temp!=0){
|
|||
|
|
printf("<EFBFBD><EFBFBD>%d<>ơA%d<><64>\n",j,temp);
|
|||
|
|
j++;
|
|||
|
|
break;
|
|||
|
|
}else{
|
|||
|
|
break;
|
|||
|
|
}
|
|||
|
|
}
|
|||
|
|
j--;
|
|||
|
|
|
|||
|
|
printf("\n<EFBFBD>̤p<EFBFBD>]<5D>˯ȭ<CBAF><C8AD>n = %d\n",(j+i+num)*2*100);
|
|||
|
|
|
|||
|
|
|
|||
|
|
return 0;
|
|||
|
|
}
|