Data_Structure/作業/test/mul_byme/main.c

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2025-01-20 21:30:53 +08:00
#include<stdio.h>
#include<stdlib.h>
void mul (int **a,int**b,int **c, int m , int k , int n){
int i , j ,l , sum;
for (i=0;i<m;i++){
for (j=0;j<n;j++){
sum = 0;
for(l=0;l<k;l++){
sum += a[i][l]*b[l][j];
}c[i][j]=sum;
}
}
}
int main(){
int i , j ,m=2 , k=3 , n=4 ;
int a[2][3]={{1,2,7},{3,4,1}};
int b[3][4]={{5,6,2,4},{7,8,2,4},{7,2,6,1}};
int **arr_a = (int**)malloc( m *sizeof(int*));
int **arr_b = (int**)malloc( k *sizeof(int*));
int **arr_c = (int**)malloc( m *sizeof(int*));
for (i=0;i<m;i++){
arr_a[i] = (int*)malloc( k *sizeof(int));
arr_c[i] = (int*)malloc( n *sizeof(int));
}
for (i=0;i<k;i++){
arr_b[i] = (int*)malloc( n *sizeof(int));
}
for(i=0;i<m;i++){
for(j=0;j<k;j++){
arr_a[i][j] = a[i][j];
}
}
for(i=0;i<k;i++){
for(j=0;j<n;j++){
arr_b[i][j] = b[i][j];
}
}
mul (arr_a,arr_b,arr_c,m,k,n);
// printf("%d\n",arr_b[2][2]);
//
for(i=0;i<m;i++){
for(j=0;j<n;j++){
printf("c[%d][%d]=%d\n",i,j,arr_c[i][j]);
}
}
free(arr_a);
free(arr_b);
free(arr_c);
for (i=0;i<m;i++){
free(arr_a[i]);
free(arr_c[i]);
}
for (i=0;i<k;i++){
free(arr_b[i]);
}
return 0 ;
}